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April 18, 2014

April 18, 2014

Posted by **Tony** on Thursday, May 12, 2011 at 2:44pm.

Girls; Sample Size 68

Sample Mean 58.52

Sample Standard Deviation 8.61

Boys; Sample Size 92

Sample Mean 64.28

Sample Standard Deviation 8.96

Q1) Choose the option that gives, to two decimal places, the estimated standard error (ESE) of the difference between the sample means for girls and boys.

A 1.40 B 1.65 C 1.73 D 1.98 E 2.00 F 2.06

Q2) The two-sample z-test is to be used to determine whether there is a difference, at the 5% significance level, between the mean scores for girls and boys. Choose the TWO options that give the value of the test statistic z, to two decimal places, and the conclusion obtained from the test.

A 4.11 B 4.50 C 4.86

D 5.00 E 8.77 F 87.71

G There seems to be a significant difference, at the 5% significance level, between the mean scores for girls and boys.

H There seems to be no significant difference, at the 5% significance level, between the mean scores for girls and boys.

- Math -
**PsyDAG**, Friday, May 13, 2011 at 12:12pmZ = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√(n-1)

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.

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