Posted by **Tony** on Thursday, May 12, 2011 at 11:52am.

Using 3(x-3)(x^2-6x+23)^1/2, as the chain rule differentiation of f(x)=(x^2-6x+23). Please explain how I find the general solution to the differential equation dy/dx= 2/27(x-3)SQUARE ROOT BEGINS (x^2-6x+23)/y SQUARE ROOT ENDS (y>0). In implicit form I have an answer of 18*y*square root of y =TOP LINE OF FRACTION is 2*(x^2-6x+23)^3/2 divided by 3, plus constant.Is this right ans what is c and using the answer what is the particular solution for which y=2 when x=1, written then in explicit form? Thank you for any response. Best wishes.

- Calculus -
**Mgraph**, Thursday, May 12, 2011 at 4:28pm
This is right

## Answer this Question

## Related Questions

- calculus - I posted this below, and no one answered. Please help with this very ...
- calculus - I posted this below, and no one answered. Please help with this very ...
- calculus - Please help with this very complicated question! Using 3(x-3)(x^2-6x+...
- calculus - Please help. How do I seperate the variables in the following ...
- Math PLEASE HELP ASAP - -PLEASE INCLUDE SOLUTIONS AND EXPLAIN HOW YOU DID IT ...
- algebra - 1.)correct 2.)wrong---> the first term is wrong 4(3a^2)^2 = 36a^4 3...
- calculus - how do you find the dy/dx of the square root of x minus the square ...
- Math - Calculus Question. - hey can someone explain to me the relationship ...
- Algebra - Use the quadratic formula to solve the equation. Give exact answers: ...
- Math simplifying mixed radicals - Please help me simplify these following mixed ...