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March 31, 2015

March 31, 2015

Posted by **Vania** on Thursday, May 12, 2011 at 2:22am.

(sec x/csc x minus cot x) minus (sec x/csc x + cot x)= 2 csc x

- pre cal -
**Reiny**, Thursday, May 12, 2011 at 7:35amIs it

(sec x/(csc x - cot x) - (sec x/(csc x + cot x))= 2 csc x or

sec x/csc x - cot x - sec x/csc x + cot x= 2 csc x

The way you typed it, according to order of operation, it would be that last one, but that is not an identity.

so

(sec x/(csc x - cot x) - (sec x/(csc x + cot x))= 2 csc x

LS = (secxcscx + secxcotx - secxcscx + secxcotx)/(csc^2x - cot^2x)

= 2secxcotx/(csc^2x - (csc^2x - 1))

= 2(1/cosx)(cosx/sinx)

= 2/sinx

= 2cscx

= RS

- pre cal -
**andy**, Thursday, May 12, 2011 at 11:48amNeed some help with this: find all solutions of cot^2 x=3 in the interval [0,2pi)

- pre cal -
**Anonymous**, Tuesday, May 17, 2011 at 1:21amVerify the Identity for (1-tanx)^2 = sec^2x-2tanx

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