Posted by John on Wednesday, May 11, 2011 at 11:12pm.
Intergral from 2 to 2 (2 is at the bottom of the integral sign and 2 is at the top) x^2dx = x^1] (the bracket has a 2 at the top and 2 at the bottom) = (2)^1((2)^1) = (1/2)(1/2) = 1
Is this true or false. I think it's false, but can someone explain to me why it's false.

CALCULUS HELP PLEASE!!  Reiny, Thursday, May 12, 2011 at 7:48am
The question is done correctly.
When you differentiate
x^1 you get x^2
and all the arithmetic was done correctly.
If this an "area between curves" type, I have seen this before.
The function f(x) = 1/x^2 is discontinuous at x=0
so even though calculationwise we come up with the answer above, it would be meaningless. 
CALCULUS HELP PLEASE!!  Mgraph, Thursday, May 12, 2011 at 2:53pm
The answer is wrong because function x^(2)>0 on [2,2] except x=0 =>integral>0
This is Improper integral which is divergent.
x^(1)>infinity if x>0