Tuesday

March 31, 2015

March 31, 2015

Posted by **albert** on Wednesday, May 11, 2011 at 6:28pm.

ʃ (cos(4x) + 2x^2)(sin(4x) − x) dx.

In each option, c is an arbitrary constant.

Options

A cos(4x) + 2x^2 +c

B -1/8cos(4x) + 2x^2)^2 +c

C 1/4 (sin(4x) − x)^2 + c

D (1/(2 (sin(4x) − x)) +c

E ln cos(4x) + 2x^2 +c

F ln (sin(4x) − x) + c

G ln (cos(4x) + 2x^2)/(sin(4x) – x)+ c

H ln (2x^2 sin(4x) − x cos(4x))+ c

- maths -
**Mgraph**, Wednesday, May 11, 2011 at 6:39pmB in form: -1/8(cos(4x)+2x^2)^2+C

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