Posted by Allison on Wednesday, May 11, 2011 at 2:18am.
Let the final velocity of the gas atom be V, and its mass be a*m, where a is a constant and m is the proton mass. Linear (x) momentum and total kinetic energy are conserved. Use classical mechanics since velocities are less than 0.15c, and because I am lazy.
m*3.9*10^7 = -m*3.7*10^7 + a*m*V
(1/2)m*(3.9)^2*10*14 = (1/2)*m*(3.7)^2*10^14 + (a*m/2)V^2
Cancel out the m's.
7.6*10^7 = a V
15.21*10^14 = 13.69*10^14 + a V^2
1.52*10^14 = a V^2
57.76*10^14 = a^2 V^2
a = 38
V = 2.00*10^6 m/s
A relativistic solution might be slightly different.
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