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September 18, 2014

September 18, 2014

Posted by **Addie** on Wednesday, May 11, 2011 at 12:06am.

- Physics -
**drwls**, Wednesday, May 11, 2011 at 1:55amIt reaches a height H such that

M g H = (1/2) M Vo^2, therefore

H = Vo^2/(2g)

g = 32.2 ft/s^2 Vo is the initial velocity

H = 99.4 feet

Time going up = Vo/g = 2.48 s

The time coming down is the same.

Total time in the air = 4.96 s

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