Sunday

October 26, 2014

October 26, 2014

Posted by **James** on Tuesday, May 10, 2011 at 11:53pm.

Please show steps.

Thanks.

- Calculus -
**Anonymous**, Wednesday, May 11, 2011 at 3:36amy–y0=f'(x0)*(x–x0)

f'=1/(3x+1)^2

x0=2

y0=2/(3*2+1)=2/(6+1)=2/7

f'(x0)=1/(3*2+1)^2=1/(6+1)^2=1/7^2=1/49

y–y0=f'(x0)*(x–x0)

y - 2/7 = 1/49*(x-2)

y=(1/49)*x - 2/49 + 2/7

y=(1/49)*x - 2/49 + 14/49

y=(1/49)*x - 12/49

y=(1/49)*(x-12)

- Calculus -
**Anonymous**, Wednesday, May 11, 2011 at 3:43amIf You don't know how find derivation of x/(3x+1) in google type: calc101

When you open page calc101com click option derivatives.In rectangle type:

x/(3x+1)

and click option DO IT

You will see solution step by step

**Answer this Question**

**Related Questions**

Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...

Calculus - Damon - Find the line which passes through the point (0, 1/4) and is ...

Calculus - If F(x)=x^3−7x+5, use the limit definition of the derivative to...

calculus - -find the equation of the tangent line to the curve y=5xcosx at the ...

calculus - find the equation of a quadratic function whose graph is tangent at x...

calculus - Consider the function y=x/(x+1) a) Find dy/dx b) Find the equation of...

calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...

please help; calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+...

cal - find the equation of a quadratic function whose graph is tangent at x=1 to...

Calculus - Consider the curve given by y^2 = 2+xy (a) show that dy/dx= y/(2y-x...