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July 22, 2014

July 22, 2014

Posted by **James** on Tuesday, May 10, 2011 at 11:53pm.

Please show steps.

Thanks.

- Calculus -
**Anonymous**, Wednesday, May 11, 2011 at 3:36amy–y0=f'(x0)*(x–x0)

f'=1/(3x+1)^2

x0=2

y0=2/(3*2+1)=2/(6+1)=2/7

f'(x0)=1/(3*2+1)^2=1/(6+1)^2=1/7^2=1/49

y–y0=f'(x0)*(x–x0)

y - 2/7 = 1/49*(x-2)

y=(1/49)*x - 2/49 + 2/7

y=(1/49)*x - 2/49 + 14/49

y=(1/49)*x - 12/49

y=(1/49)*(x-12)

- Calculus -
**Anonymous**, Wednesday, May 11, 2011 at 3:43amIf You don't know how find derivation of x/(3x+1) in google type: calc101

When you open page calc101com click option derivatives.In rectangle type:

x/(3x+1)

and click option DO IT

You will see solution step by step

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