math
posted by fernanda .
the length of a rectangular field is 18 m longer than the width. the field is enclosed with fencing and divided into two parts with a fence parallel to the shoter sides. if 216 m of fencing are required to the shoter sides. if 216 m of fencing are required, what are the dimensions of the outside rectangle?

shorter side  x
longer side  x+18
wouldn't we just get
2(x+18) + 3x = 216 ???
I get short side = 36
long side = 54 
1944