Posted by **andy** on Tuesday, May 10, 2011 at 9:31pm.

Let (theta) be an angle in quadrant II such that csc(theta)=8/5 Find the exact value of tan(theta) and cos(theta).

- trig -
**Reiny**, Tuesday, May 10, 2011 at 10:39pm
if csc Ø = 8/5

then

sin Ø = 5/8

I see a right-angled triangle with hypotenuse 8 and vertical side (the y) of 5

By Pythagoras, the other side is √39

in II both cosine and tangent are negative, so

tanØ = -5/√39

cosØ = -√39/8

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