trig
posted by andy on .
Let (theta) be an angle in quadrant II such that csc(theta)=8/5 Find the exact value of tan(theta) and cos(theta).

if csc Ø = 8/5
then
sin Ø = 5/8
I see a rightangled triangle with hypotenuse 8 and vertical side (the y) of 5
By Pythagoras, the other side is √39
in II both cosine and tangent are negative, so
tanØ = 5/√39
cosØ = √39/8