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November 26, 2014

November 26, 2014

Posted by **Akansha** on Tuesday, May 10, 2011 at 7:26pm.

and

find the area of the region bounded by the curve y=e^2x -3e^x + 2 and the x-axis?

- Calculus -
**Damon**, Tuesday, May 10, 2011 at 8:25pmWhere do they intersect?

3x = x^3 + 2 x^2

x^3 + 2 x^2 - 3 x = 0

x (x^2 + 2x -3) = 0

x (x+3)(x-1) = 0

intersect at x = -3, 0, 1

from x = -3 to x = 0 the cubic is above the line so in that domain the area is integral [ x^3 + 2 x^2 - 3 x] dx

from x = 0 to x = 1 the line is above the cubic so in that domain the area is

integral [ 3 x - x^3 - 2 x^2] dx

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