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Posted by on Tuesday, May 10, 2011 at 4:50pm.

SOLVE:

(3x-5)^3


that's to the third power

  • College Algebra - , Tuesday, May 10, 2011 at 5:14pm

    Solving implies that you are dealing with an equation.
    You did not give an equation.

  • College Algebra - , Tuesday, May 10, 2011 at 5:32pm

    sorry ...it is cubing binomials and the avove problem

  • College Algebra - , Tuesday, May 10, 2011 at 5:55pm

    What is it equal to??
    You still did not state the "equation"

    It should look something like

    (3x-5)^3 = ????

    are you just expanding (3x+5)^3
    you could do it the long way by doing
    (3x+5)(3x+5)(3x+5)

    or you could use Pascal's triangle whose third row has coefficients 1 3 3 1
    so
    (3x+5)
    = 1(3x)^3 + 3(3x^2)(5) + 3(3x)(5^2) + 5^3
    = 27x^3 + 135x^2 + 225x + 125

  • College Algebra - , Tuesday, May 10, 2011 at 5:57pm

    great!!! thanks so much ...... you are a life saver!!!!! =)

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