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February 27, 2015

February 27, 2015

Posted by **Nancy** on Tuesday, May 10, 2011 at 4:50pm.

(3x-5)^3

that's to the third power

- College Algebra -
**Reiny**, Tuesday, May 10, 2011 at 5:14pmSolving implies that you are dealing with an equation.

You did not give an equation.

- College Algebra -
**Nancy**, Tuesday, May 10, 2011 at 5:32pmsorry ...it is cubing binomials and the avove problem

- College Algebra -
**Reiny**, Tuesday, May 10, 2011 at 5:55pmWhat is it equal to??

You still did not state the "equation"

It should look something like

(3x-5)^3 = ????

are you just expanding (3x+5)^3

you could do it the long way by doing

(3x+5)(3x+5)(3x+5)

or you could use Pascal's triangle whose third row has coefficients 1 3 3 1

so

(3x+5)

= 1(3x)^3 + 3(3x^2)(5) + 3(3x)(5^2) + 5^3

= 27x^3 + 135x^2 + 225x + 125

- College Algebra -
**Nancy**, Tuesday, May 10, 2011 at 5:57pmgreat!!! thanks so much ...... you are a life saver!!!!! =)

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