If 12.50 mL of 0.324 M HCl is diluted to 250.00 mL, what is the concentration of HCl in the final solution?
mL1 x M1 = mL2 x M2
To find the concentration of HCl in the final solution, you can use the formula for dilution.
The formula for dilution is:
M1V1 = M2V2
Where:
M1 = initial concentration of the solution
V1 = initial volume of the solution
M2 = final concentration of the solution
V2 = final volume of the solution
Given:
M1 = 0.324 M
V1 = 12.50 mL
V2 = 250.00 mL
Let's substitute these values into the formula:
0.324 M * 12.50 mL = M2 * 250.00 mL
Simplifying the equation:
4.05 = M2 * 250
Now, divide both sides of the equation by 250 to solve for M2:
M2 = 4.05 / 250
M2 = 0.0162 M
Therefore, the concentration of HCl in the final solution is 0.0162 M.
To find the concentration of HCl in the final solution, we need to use the concept of dilution. Dilution is a process in which a concentrated solution is mixed with a solvent to obtain a solution with a lower concentration.
In this case, we have 12.50 mL of a 0.324 M HCl solution that we are diluting to a total volume of 250.00 mL.
To solve this problem, we can use the equation:
C1V1 = C2V2
Where:
C1 = initial concentration
V1 = initial volume
C2 = final concentration
V2 = final volume
Let's plug in the values we have:
C1 = 0.324 M
V1 = 12.50 mL
V2 = 250.00 mL
Now solving for C2:
C2 = (C1 * V1) / V2
C2 = (0.324 M * 12.50 mL) / 250.00 mL
C2 = 0.0162 M
Therefore, the concentration of HCl in the final solution is 0.0162 M.