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Posted by on Tuesday, May 10, 2011 at 2:29pm.

Find the surface area of the closed rectangular box shown

6cm, 5cm, 3cm
S.A.= (LW)+2(HL)+2(HW)

I did: (5x6)+2(5x3)+2(6x3)=96 am I correct?

  • Essential Mathematics 2 - , Tuesday, May 10, 2011 at 4:01pm

    6cm, 5cm, 3cm
    This formula for the surface area is for an open box with length L and width W:
    S.A.(open)= (LW)+2(HL)+2(HW)

    For a closed box, it would be:
    S.A.(closed)= 2(LW+HL+HW)


    You would do: 2(5x6)+2(5x3)+2(6x3)=?

  • Essential Mathematics 2 - , Tuesday, May 10, 2011 at 5:11pm

    126. thanks

  • Essential Mathematics 2 :) - , Tuesday, May 10, 2011 at 5:16pm

    You're welcome!

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