Saturday

March 28, 2015

March 28, 2015

Posted by **Mike** on Tuesday, May 10, 2011 at 2:25pm.

- Math -
**Henry**, Wednesday, May 11, 2011 at 4:37pm1. Draw line segment AB.

2. Draw the 14-degree angle from point

A.

3. Draw the 34-degree angle from point B. Label the intersection of these 2 lines point C. Now we have formed

triangle ABC.

4. Draw the altitude from point C perpendicular to AB and label it CD.

The distance of the fire from AB is

equal to the altitude(CD).

A + B + C = 180 Deg.

14 + 34 + C = 180,

C = 132 Deg.

a/sinA = c/sinC,

a/sin14 = 30/sin132,

Multiply both sides by sin14:

a = 30sin14 / sin132 = 9.77km.

CD = 9.77sin34 = 5.46km = dist. from

fire to AB.

- Math -
**sam**, Wednesday, December 4, 2013 at 5:50am21.9

**Answer this Question**

**Related Questions**

Trigonometry - Two fire towers are 30 km apart, tower A being due west of tower ...

Pre-Calculus - I need help with this problem: The bearing from the Pine Knob ...

Trigonometry (Law of Sine) - Fire towers A and B are located 10 miles apart. ...

Trigonometry (Law of Sine) - Fire towers A and B are located 10 miles apart. ...

Grade 11 Math - I have two questions two forest fire towers, A and B are 20.3km ...

Math - Two fire towers, A and B, are 20.3 km apart. From tower A, the bearing of...

Pre-Calc - Two lookout towers on Mount Abraham and Snow Mountain are 29 miles ...

Principles of Math 11 - A ranger in fire tower A spots a fire at a bearingof 295...

math - two office towers are 31 m apart. From the top of the shorter tower, the ...

math trigonometry - two office towers are 31 m apart. From the top of the ...