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July 25, 2014

July 25, 2014

Posted by **Mike** on Tuesday, May 10, 2011 at 2:25pm.

- Math -
**Henry**, Wednesday, May 11, 2011 at 4:37pm1. Draw line segment AB.

2. Draw the 14-degree angle from point

A.

3. Draw the 34-degree angle from point B. Label the intersection of these 2 lines point C. Now we have formed

triangle ABC.

4. Draw the altitude from point C perpendicular to AB and label it CD.

The distance of the fire from AB is

equal to the altitude(CD).

A + B + C = 180 Deg.

14 + 34 + C = 180,

C = 132 Deg.

a/sinA = c/sinC,

a/sin14 = 30/sin132,

Multiply both sides by sin14:

a = 30sin14 / sin132 = 9.77km.

CD = 9.77sin34 = 5.46km = dist. from

fire to AB.

- Math -
**sam**, Wednesday, December 4, 2013 at 5:50am21.9

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