If the soda you are drinking contains 0.5% by mass sodium benzoate as a preservative. What approximate mass of sodium benzoate is contained in 1.00 L of the solution assuming that the density of the soda is 1.00 g/mL(the approximate density of water)?

0.5% w/w means 0.5 g sodium benzoate in 100 g soln. Therefore, in 1000 g soln (1000 mL with a density of 1.00 g/mL), there will be 5 g sodium benzoate (0.5g x 1000/100), right?

To find the approximate mass of sodium benzoate in 1.00 L of the solution, we need to consider the density of the soda and the percentage by mass of sodium benzoate.

Step 1: Calculate the mass of the soda.
Since the density of the soda is 1.00 g/mL, the mass of 1.00 L of the soda is 1.00 kg (since 1 mL of water is approximately equal to 1 g).

Step 2: Calculate the mass of sodium benzoate.
The soda contains 0.5% by mass of sodium benzoate. This means that for every 100 g of the soda, there is 0.5 g of sodium benzoate.

To calculate the mass of sodium benzoate in 1.00 L of the soda, we multiply the mass of the soda by the percentage of sodium benzoate:

Mass of sodium benzoate = (0.5 g/100 g) * 1,000 g

Step 3: Calculate the mass of sodium benzoate.
Mass of sodium benzoate = 5 g

Therefore, approximately 5 grams of sodium benzoate is contained in 1.00 L of the soda.

To calculate the mass of sodium benzoate in 1.00 L of the soda solution, we first need to determine the mass of the solution itself.

Given that the density of the soda is 1.00 g/mL, we can assume that the mass of 1.00 L of the solution is 1,000 g (since 1 L = 1,000 mL).

Now, we can calculate the mass of sodium benzoate using the information that it makes up 0.5% of the solution by mass.

0.5% is equivalent to 0.005 as a decimal.

So, to find the mass of sodium benzoate, we multiply the mass of the solution (1,000 g) by 0.005:

Mass of sodium benzoate = 1,000 g * 0.005 = 5 g

Therefore, approximately 5 grams of sodium benzoate is contained in 1.00 L of the soda solution.