Posted by yengiang on Monday, May 9, 2011 at 10:22am.
a/ Sorry, it was what's A intersection B?
A={n ∈ Z| 2 divides n}
B={n ∈ Z| 3 divides n}
A∩B
={n in Z| 2|n and 3|n}
={n in Z| 6|n}
That is
A∩B is the set of all integers divisible by 6.
A'={n in Z| 2∤n}
= all odd integers.
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