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July 30, 2014

July 30, 2014

Posted by **anonymous** on Sunday, May 8, 2011 at 11:42pm.

b)Nuclear reactions can produce electrically charged particles (of say mass m and charge q). To measure the kinetic energy E of such a particle we want to find its speed v, and one way to do this in practice is to use a magnetic field (of constant magnitude B, and perpendicular to the particle's direction of motion). The Lorentz force law tells us that such a particle traveling though the magnetic field will experience a force of magnitude q v B. What direction does the force point in? Explain why this causes the particle to move in a circle, and derive a formula that gives the kinetic energy of the particle in terms of the (observable) radius of this circle.

- physics-nuclear reactors -
**john**, Monday, May 9, 2011 at 12:56amthis sso guy is nuts if he thinks we should be able to do this...

- physics-nuclear reactors -
**Damon**, Monday, May 9, 2011 at 6:11ama)

E = m c^2

here

m = .05 grams = .05*10^-3 kg = 5*10^-5 kg

c = 3*10^8m/s so c^2 = 9*10^16 m^2/s^2

so

E = 45 * 10^11 = 4.5*10^12 Joules

b) Force perpendicular to velocity gives centripetal acceleration

F = m v^2/R

so

q v B = m v^2/R

so

v = (q/m) B R

Ke = (1/2) m v^2

Ke = (1/2) m (q/m)^2 B^2 R^2

Ke = (1/2) (q B R)^2 sqrt(m)

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