Posted by Anna- on Sunday, May 8, 2011 at 7:54pm.
well, the first multiple of 5 in that interval is 105.
The last is 2000.
105 + 110 + 115 + ........ 2000
n-1 = (2000-105)/5 = 379
n = 380
Sum = (n/2)(a1+an) = (380/2)(2105)
=399,950
Thank you very much
You are welcome :)
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