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March 29, 2017

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A small electric motor is used to lift a
0.50-kilogram mass at constant speed. If the
mass is lifted a vertical distance of 1.5 meters in
5.0 seconds, the average power developed by the
motor is

  • physics ---- really dnt get this at all - ,

    See if any of the following links will help:

    http://search.yahoo.com/search?fr=mcafee&p=how+to+figure+the+average+power+of+a+motor

    Sra

  • physics ---- really dnt get this at all - ,

    change in potential energy = m g h

    energy/time = power = m g h /t

    = .50 * 9.81 * 1.5 / 5

    Joules/second or Watts

  • physics ---- really dnt get this at all - ,

    calculate the power out in watts and horse power of an 80 kg man that climbs a flight of stairs 5.8m high in 4.0s.

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