Posted by **ashley --- HELP PLEASEE!!!** on Sunday, May 8, 2011 at 3:54pm.

A small electric motor is used to lift a

0.50-kilogram mass at constant speed. If the

mass is lifted a vertical distance of 1.5 meters in

5.0 seconds, the average power developed by the

motor is

- physics ---- really dnt get this at all -
**SraJMcGin**, Sunday, May 8, 2011 at 4:05pm
See if any of the following links will help:

http://search.yahoo.com/search?fr=mcafee&p=how+to+figure+the+average+power+of+a+motor

Sra

- physics ---- really dnt get this at all -
**Damon**, Sunday, May 8, 2011 at 5:06pm
change in potential energy = m g h

energy/time = power = m g h /t

= .50 * 9.81 * 1.5 / 5

Joules/second or Watts

- physics ---- really dnt get this at all -
**Yangtze**, Sunday, November 20, 2011 at 6:05am
calculate the power out in watts and horse power of an 80 kg man that climbs a flight of stairs 5.8m high in 4.0s.

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