HC2H3O2 + CH3(CH2)4OH (H2SO4)=?
acid + alcohol ==> ester + water
CH3COOH + HO(CH2)4CH3 ==>
CH3COO(CH2)4CH3 + H2O
pentyl acetate, an ester.
http://en.wikipedia.org/wiki/Amyl_acetate
To determine the products of the reaction between HC2H3O2 (acetic acid) and CH3(CH2)4OH (butanol) in the presence of H2SO4 (sulfuric acid), we first need to consider the reaction conditions.
The reaction you provided seems to be the esterification reaction, also known as Fischer esterification. In this reaction, an acid (acetic acid) reacts with an alcohol (butanol) in the presence of an acid catalyst (sulfuric acid) to produce an ester.
The balanced chemical equation for the reaction is as follows:
HC2H3O2 + CH3(CH2)4OH → CH3(CH2)4OC2H3O2 + H2O
In this equation, the acetic acid (HC2H3O2) reacts with butanol (CH3(CH2)4OH) to produce butyl acetate (CH3(CH2)4OC2H3O2) and water (H2O).
Therefore, the products of the reaction are butyl acetate and water.