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July 29, 2014

July 29, 2014

Posted by **Nick** on Sunday, May 8, 2011 at 12:35am.

- trig -
**Reiny**, Sunday, May 8, 2011 at 8:15amIf sec Ø = 7

then cosØ = 1/7

Also since sinØ < 0, then Ø must be an angle in quadrant IV

From the right-triangle drawn in standard position, the missing side would be √48 or 4√3

sinØ = -4√3/7

cscØ = -7/(4√3)

cosØ = 1/7

secØ = 7 , (that was given)

tanØ = -1/(4√3)

cotØ = -4√3

- HEEM! -
**Suck**, Monday, May 16, 2011 at 10:43amneed help idkk wtf yall talkingg boutt

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