Use the Ideal Gas Law to determine the volume of CO2 produced at 25oC 1.5 atm of pressure from the combustion of 35 grams of C6H10.
balance the reaction equation:
2C6H10+17O2>>12CO2 + 10H20 check that.
so you get 12 moles CO2 for each 2 mole of C6H10
molesCO2=12/2 * moles C6H10=6*35/molmassC6H10
figure that out. Then,
PV=nRT
V=nRT/P where n is moles CO2, you are given T (change it to K). Watch units of R, you are in kelvins, atm
To use the Ideal Gas Law to determine the volume of CO2 produced, we need to know the molar mass of C6H10 (which is the molecular formula for cyclohexene) and the stoichiometry of its combustion reaction.
Here are the steps to find the volume of CO2 produced:
Step 1: Find the moles of C6H10.
Given: mass of C6H10 = 35 grams
Find: moles of C6H10
To find the moles, we need to divide the mass by the molar mass of C6H10. The molar mass can be found by adding up the atomic masses of all the atoms in the molecule (as given by the periodic table):
C: 12.01 g/mol (carbon)
H: 1.01 g/mol (hydrogen)
Molar mass of C6H10 = (6 * 12.01 g/mol) + (10 * 1.01 g/mol)
Step 2: Determine the stoichiometry of the combustion reaction.
The balanced combustion equation will give us the mole ratio between C6H10 and CO2. Assuming complete combustion, the equation is:
C6H10 + (15/2) O2 -> 6 CO2 + 5 H2O
From the combustion equation, we can see that for every mole of C6H10, we get 6 moles of CO2.
Step 3: Calculate the moles of CO2 produced.
Given the moles of C6H10, we can use the mole ratio from the balanced equation to find the moles of CO2 produced:
moles of CO2 = moles of C6H10 * (6 moles of CO2 / 1 mole of C6H10)
Step 4: Apply the Ideal Gas Law to find the volume of CO2.
The Ideal Gas Law equation is as follows:
PV = nRT
Where:
P = pressure (1.5 atm)
V = volume (unknown)
n = moles of CO2
R = ideal gas constant (0.0821 atm L / mol K)
T = temperature (25 degrees Celsius = 298 Kelvin)
To find the volume (V), rearrange the Ideal Gas Law equation:
V = (nRT) / P
Substitute the values obtained from previous steps into the equation and solve for V.
Once you have performed these calculations, you will find the volume of CO2 produced from the combustion of 35 grams of C6H10 at 25 degrees Celsius and 1.5 atm of pressure.