Posted by Anonymous on Saturday, May 7, 2011 at 12:37am.
Lead pellets of total mass 0.46 kg are heated to 107 C and then placed in a wellinsulated aluminum cup of mass 0.15 kg that contains 0.52 kg of water initially at 13.8 C. What is the equilibrium temperature of the mixture?

Physics  drwls, Saturday, May 7, 2011 at 8:09am
Heat lost by lead = heat gained by water.
Write that with T(final) as the only unknown, using masses and specific heats, and solve for T(final), the equilibrium temperature.
You will need to look up the lead specific heat. I am sure you know the value for water.
None of the water will boil away in this case

Physics  Amy, Saturday, May 7, 2011 at 10:24pm
Can you help me solve the problem bc I tried to do it as you said but I'm getting the wrong answer.
Answer This Question
Related Questions
 Physics  Lead pellets of total mass 0.46 kg are heated to 107 C and then placed...
 physics  Suppose 0.0290 kg of steam (at 100.00°C) is added to 0.290 kg of water...
 Physics  Suppose 0.015 kg of steam (at 100.00 °C) is added to 0.20 kg of water...
 science  Ice cubes of total mass 6.00 grams have temperature 4.0°C. Then they...
 Physics  An aluminum spoon at 84 C is placed in a Styrofoam cup containing 0....
 Science  A lead calorimeter with mass of 150g contains 200g of water. The ...
 Science  A lead calorimeter with mass of 150g contains 200g of water. The ...
 Physics  An alloy of mass 225g is heated to 550C. It is quickly placed in 450g ...
 physics  Suppose 0.0150 kg of steam (at 100.00°C) is added to 0.150 kg of water...
 physics  Suppose 0.0150 kg of steam (at 100.00°C) is added to 0.150 kg of water...
More Related Questions