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July 29, 2014

July 29, 2014

Posted by **Math** on Friday, May 6, 2011 at 11:52pm.

- Algebra -
**drwls**, Saturday, May 7, 2011 at 12:20amThe distance between the trains decreases at a rate ot 4 mph.

When train B passes the station, at 12:45, train A is 50 miles ahead. (100 mph x 1/2 hour)

The time required for train B to catch up is 50 miles/4 mph = 12.5 hours.

The time will then be 1:15 AM

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