Posted by **Math** on Friday, May 6, 2011 at 11:52pm.

Train A is traveling at 100 mph and train B is traveling at 104 mph. Train A passes a station at 12:15 p.m. If train B passes the same station at 12:45 p.m., at what time will train B catch up to train A? HELP please I am drawing a complete balank at figuring the how to solve this.

- Algebra -
**drwls**, Saturday, May 7, 2011 at 12:20am
The distance between the trains decreases at a rate ot 4 mph.

When train B passes the station, at 12:45, train A is 50 miles ahead. (100 mph x 1/2 hour)

The time required for train B to catch up is 50 miles/4 mph = 12.5 hours.

The time will then be 1:15 AM

## Answer This Question

## Related Questions

- Algebra Help PLZ - I have tried this several different ways and I am just not ...
- algebra - Trains A and B are traveling in the same direction on parrallel tracks...
- algebra - Train A and B are traveling in the same direction on parallel tracks. ...
- algebra - Trains A and B are traveling in the same direction on parrallel ...
- math/algebra - Trains A and B are traveling in the same direction on parallel ...
- math algebra - Trains A and B are traveling the same direction on parallel ...
- Algebra - Trains A and B are traveling in the same direction on parallel tracks...
- math - Trains A and B are traveling in the same direction on parrallel tracks. ...
- algebra - Train A and B are traveling in the same direction on parallel tracks. ...
- algebra - Train A and B are traveling in the same direction on parallel tracks. ...

More Related Questions