Saturday

October 25, 2014

October 25, 2014

Posted by **Math** on Friday, May 6, 2011 at 11:52pm.

- Algebra -
**drwls**, Saturday, May 7, 2011 at 12:20amThe distance between the trains decreases at a rate ot 4 mph.

When train B passes the station, at 12:45, train A is 50 miles ahead. (100 mph x 1/2 hour)

The time required for train B to catch up is 50 miles/4 mph = 12.5 hours.

The time will then be 1:15 AM

**Answer this Question**

**Related Questions**

Algebra Help PLZ - I have tried this several different ways and I am just not ...

algebra - Trains A and B are traveling in the same direction on parrallel tracks...

math/algebra - Trains A and B are traveling in the same direction on parallel ...

math algebra - Trains A and B are traveling the same direction on parallel ...

algebra - Trains A and B are traveling in the same direction on parrallel ...

algebra - Train A and B are traveling in the same direction on parallel tracks. ...

Algebra - Trains A and B are traveling in the same direction on parallel tracks...

algebra - Train A and B are traveling in the same direction on parallel tracks. ...

algebra - Train A and B are traveling in the same direction on parallel tracks. ...

algebra - Trains A and B are traveling in the same direction on parallel tracks...