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Algebra

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Train A is traveling at 100 mph and train B is traveling at 104 mph. Train A passes a station at 12:15 p.m. If train B passes the same station at 12:45 p.m., at what time will train B catch up to train A? HELP please I am drawing a complete balank at figuring the how to solve this.

  • Algebra -

    The distance between the trains decreases at a rate ot 4 mph.

    When train B passes the station, at 12:45, train A is 50 miles ahead. (100 mph x 1/2 hour)

    The time required for train B to catch up is 50 miles/4 mph = 12.5 hours.

    The time will then be 1:15 AM

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