Algebra
posted by Math on .
Train A is traveling at 100 mph and train B is traveling at 104 mph. Train A passes a station at 12:15 p.m. If train B passes the same station at 12:45 p.m., at what time will train B catch up to train A? HELP please I am drawing a complete balank at figuring the how to solve this.

The distance between the trains decreases at a rate ot 4 mph.
When train B passes the station, at 12:45, train A is 50 miles ahead. (100 mph x 1/2 hour)
The time required for train B to catch up is 50 miles/4 mph = 12.5 hours.
The time will then be 1:15 AM