Post a New Question

8th grade algebra: radicals

posted by on .

please help me solve these

1. 2√5/8 + 4√3/8 - 1/2√68

2. √4k-5 +1=8
(the radical sign goes over 4k-5)

3. (x+4)*2 /3 =8

4. Write the value of the discriminant of each equation. Then use it to decide how many different real-number roots the equation has.
x*2-6x+2=0

  • 8th grade algebra: radicals - ,

    Answer to number 3:

    2/3(x+4) = 8
    2(x+4) = 24
    2x+8 = 24
    2x = 16
    x = 8

  • 8th grade algebra: radicals - ,

    Answer to number 3 is wrong. (didn't realise it was x+4 to the power of two thirds. Sorry):

  • 8th grade algebra: radicals - ,

    Looks like Jenna is using * as the sign for exponents.
    In #3 , no brackets were used around the 2/3, so it has to be read as

    ((x+4)^2)/3 = 8
    then
    (x+4)^2 = 24
    x+4 = +/- sqrt(24)

    x = -4 +/- 2sqrt(6)

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question