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September 30, 2014

September 30, 2014

Posted by **jenna** on Friday, May 6, 2011 at 11:43pm.

1. 2√5/8 + 4√3/8 - 1/2√68

2. √4k-5 +1=8

(the radical sign goes over 4k-5)

3. (x+4)*2 /3 =8

4. Write the value of the discriminant of each equation. Then use it to decide how many different real-number roots the equation has.

x*2-6x+2=0

- 8th grade algebra: radicals -
**L**, Saturday, May 7, 2011 at 7:13amAnswer to number 3:

2/3(x+4) = 8

2(x+4) = 24

2x+8 = 24

2x = 16

x = 8

- 8th grade algebra: radicals -
**L**, Saturday, May 7, 2011 at 7:17amAnswer to number 3 is wrong. (didn't realise it was x+4 to the power of two thirds. Sorry):

- 8th grade algebra: radicals -
**Reiny**, Saturday, May 7, 2011 at 10:08amLooks like Jenna is using * as the sign for exponents.

In #3 , no brackets were used around the 2/3, so it has to be read as

((x+4)^2)/3 = 8

then

(x+4)^2 = 24

x+4 = +/- sqrt(24)

x = -4 +/- 2sqrt(6)

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