Posted by **Keyonna** on Friday, May 6, 2011 at 10:05am.

The ratio of the perimeters of two similar squares is 5 to 4. If the area of the smaller square is 32 square units, what is the area of the larger square?

- Math -
**Reiny**, Friday, May 6, 2011 at 10:17am
Since both the length of sides and perimeter are linear

the perimeters would be in that same ratio as the sides.

So the sides are in the ratio of 5:4

The ratio of areas is equal to the square of their corresponding sides.

so

A/32 = 5^2 / 4^2

A = 32(25)/16 = 50

- Math -
**Abdul-Rehman**, Friday, May 6, 2011 at 10:48am
If Smaller square = 32

Perimeter of Small Square = 4x

Perimeter of Larger Square = 5x

Perimeter Of Small Square = 4L

4x = 32

x = 32 / 4

x = 8

Then

5x = 5(8)

5x = 40

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