The ratio of the perimeters of two similar squares is 5 to 4. If the area of the smaller square is 32 square units, what is the area of the larger square?
Math - Reiny, Friday, May 6, 2011 at 10:17am
Since both the length of sides and perimeter are linear
the perimeters would be in that same ratio as the sides.
So the sides are in the ratio of 5:4
The ratio of areas is equal to the square of their corresponding sides.
A/32 = 5^2 / 4^2
A = 32(25)/16 = 50
Math - Abdul-Rehman, Friday, May 6, 2011 at 10:48am
If Smaller square = 32
Perimeter of Small Square = 4x
Perimeter of Larger Square = 5x
Perimeter Of Small Square = 4L
4x = 32
x = 32 / 4
x = 8
5x = 5(8)
5x = 40