Posted by **Diana** on Thursday, May 5, 2011 at 8:21pm.

The height of a golf ball that is hit into the air with an initial vertical velocity of 112 feet per second is given by the equation h=-16t^2 + 112t, where t is the time in seconds. After how many seconds is the ball at a height of 96 feet above the ground?

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**Anonymous**, Monday, May 2, 2016 at 4:25pm
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