When hydrochloric acid reacts with zinc metal, zinc chloride and hydrogen gas are produced. How many moles of hydrochloric acid are needed to react with 2.3 moles of zinc?

2HCl+Zn-ZnCl2+H2

2mol of HCl-1mol of Zn
2.3mol of Zn
2.3 times 2 = 4.6mol of HCl

To determine how many moles of hydrochloric acid are needed to react with 2.3 moles of zinc, we need to first determine the stoichiometry, or the molar ratios, between hydrochloric acid and zinc in the balanced chemical equation.

The balanced chemical equation for the reaction is:

Zn + 2HCl -> ZnCl2 + H2

From the balanced equation, we can see that the molar ratio between zinc (Zn) and hydrochloric acid (HCl) is 1:2. This means that for every 1 mole of zinc, we need 2 moles of hydrochloric acid.

Given that we have 2.3 moles of zinc, we can use the molar ratio to calculate the moles of hydrochloric acid needed:

Moles of HCl = Moles of Zn x (Molar ratio of HCl to Zn)
= 2.3 moles x (2 moles HCl / 1 mole Zn)
= 4.6 moles of HCl

Therefore, 4.6 moles of hydrochloric acid are needed to react with 2.3 moles of zinc.