posted by Jimmy on .
Use the function below to answer the following parts.
1/3x - 4 if -6 </= x < - 3
f(x) = 2 if -3 < x < 3
x^2 - 4 if x > 3
I found out the domain, range, and points of disontinuity. I think i did them right:
and points of discontinuity = x=-3,x=3
How do i graph these functions?
Your first segment runs from (-6,-6) to (-3,-5)
for -6 ≤ x < -3
so draw a solid dot for (-6,-6) and an "open" dot for (-3,-5)
the 2nd segment runs from (-3,2) to (3,2).
draw that line leaving the end points as open dots.
the 3rd graph is part of a parabola, which has its vertex at (0,-4) and which would open upwards.
I would pass through (1,-3), (2,0) and (3,5)
draw it only from (3,5) on, leaving the (3,5) open.
you are correct with your domain and range, and your value of x that have a discontinuity.