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Posted by on Thursday, May 5, 2011 at 4:13pm.

Use the function below to answer the following parts.

1/3x - 4 if -6 </= x < - 3
f(x) = 2 if -3 < x < 3
x^2 - 4 if x > 3



I found out the domain, range, and points of disontinuity. I think i did them right:

Domain= [-6,infinity]
Range= [-6,infinity]
and points of discontinuity = x=-3,x=3

How do i graph these functions?

  • Algebra - , Thursday, May 5, 2011 at 5:09pm

    Your first segment runs from (-6,-6) to (-3,-5)
    for -6 ≤ x < -3

    so draw a solid dot for (-6,-6) and an "open" dot for (-3,-5)

    the 2nd segment runs from (-3,2) to (3,2).
    draw that line leaving the end points as open dots.

    the 3rd graph is part of a parabola, which has its vertex at (0,-4) and which would open upwards.
    I would pass through (1,-3), (2,0) and (3,5)

    draw it only from (3,5) on, leaving the (3,5) open.

    you are correct with your domain and range, and your value of x that have a discontinuity.

  • Algebra - , Thursday, May 5, 2011 at 5:36pm

    thanks

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