Calculate the pH of a solution that is made by mixing 10.00 mL of 0.2500 M HCl with 35.00 mL of .1500 M HNO3 and diluting the mixture to a total volume of 100.00 mL

To calculate the pH of the solution, you'll need to use the equation for pH:

pH = -log[H+]

First, calculate the total number of moles of H+ ions in the solution.

For HCl:
Volume (V1) = 10.00 mL
Concentration (C1) = 0.2500 M

moles of HCl = V1 x C1
= 10.00 mL x 0.2500 M
= 0.00250 moles

For HNO3:
Volume (V2) = 35.00 mL
Concentration (C2) = 0.1500 M

moles of HNO3 = V2 x C2
= 35.00 mL x 0.1500 M
= 0.00525 moles

Now, calculate the total volume of the solution after mixing.

Volume (V3) = 100.00 mL

Next, calculate the total moles of H+ ions in the solution.

Total moles of H+ = moles of HCl + moles of HNO3
= 0.00250 moles + 0.00525 moles
= 0.00775 moles

Remember that the total volume of the solution is 100.00 mL, which is equivalent to 0.1000 L. So, you can convert moles to concentration (M) using the equation:

Concentration (C) = moles / volume (L)

Concentration of H+ ions = Total moles of H+ / Total volume
= 0.00775 moles / 0.1000 L
= 0.0775 M

Finally, calculate the pH using the equation:

pH = -log[H+]

pH = -log(0.0775)
pH ≈ 1.11

Therefore, the pH of the solution is approximately 1.11.