Thursday

December 18, 2014

December 18, 2014

Posted by **Anonymous** on Thursday, May 5, 2011 at 2:16pm.

- calculus -
**bobpursley**, Thursday, May 5, 2011 at 2:22pm500=areabase* h

take the derivative.

0=d areabase/dt * h+ areabase*dh/dt

solve for dh/dt when

areabase=18^2

h= 500/18^2

dareabase/dt=3 cm^2/sec

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