posted by Loren on .
Methyl alcohol (wood alcohol), CH3OH, is produced via the reaction
CO(g) + 2 H2(g) à CH3OH(l)
A mixture of 1.20 g H2(g) and 7.45 g CO(g) are allowed to react. 4 points
(a) Which reagent is the limiting reagent?
(b) What is the yield of CH3OH? [Assume theoretical yield in g is what is wanted here.]
(c) How much of the reagent present in excess is left over?
(d) Suppose the actual yield is 7.52 g of CH3OH. What is the % yield?