(1/m)= (m-34)/(2m^2)

we cross-multiply:
2m^2 = m(m-34)
2m^2 = m^2 - 34m
m^2 + 34m = 0
m(m+34) = 0
m = 0 and m = -34
but note that m = 0 is extraneous since when substituted back to original,
1/0 = (0-34)/(2*0^2)
and any number divided by zero is undefined. thus
x = -34 only.

hope this helps~ :)

(X t 2)3

To solve for the value of m in the equation (1/m) = (m-34)/(2m^2), we can cross-multiply to eliminate the fractions.

First, multiply both sides of the equation by m to get rid of the fraction on the left side:

1 = (m-34)/(2m)

Next, cross-multiply by multiplying both sides of the equation by 2m:

2m = m - 34

Now, we can solve for m by isolating the m term on one side of the equation:

2m - m = -34

Simplifying the left side:

m = -34

Thus, the value of m is -34.