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July 24, 2016
Posted by **Amy** on Thursday, May 5, 2011 at 4:44am.

2.) ∫ sec^2x tanx dx

3.) ∫ 2 csc^2 xdx

4.) ∫ (3) / sqtr(x+3) dx

5.) ∫ (2x-1) / (x^2 - x)

- Help Evaluating Integrals -
**drwls**, Thursday, May 5, 2011 at 8:46am5.) (2x-1) dx / (x^2 - x)

let x^2 -x = u

du = 2x -1

Integral = du/u = ln u = ln(x^2-u)