the sum of the ages is 48, Bailey's mom is 15 more than twice his age. what is the ages of the two?
b is bailey and m is bailey's mom
b+m=48
given
m=2b+15;
substitute
2b+15+b=48
b=11;
where 11+m=48;
48-11=m;
m=37;
b=11 and m=37
Bailey --- x
Mom ---- 2x+15
solve
x + 2x+15 = 48
To solve this problem, let's break it down step by step.
1. Let's define the variables:
- Let Bailey's age be represented by the letter "B".
- Let Bailey's mom's age be represented by the letter "M".
2. According to the problem, the sum of their ages is 48:
B + M = 48
3. The problem also states that Bailey's mom is 15 more than twice his age:
M = 2B + 15
Now we have a system of two equations:
B + M = 48
M = 2B + 15
To solve this system, we can use the substitution method or the elimination method. Let's use the substitution method.
Solve Equation 2 for "M":
M = 2B + 15
Substitute this value into Equation 1:
B + (2B + 15) = 48
Combine like terms:
3B + 15 = 48
Subtract 15 from both sides:
3B = 33
Divide both sides by 3:
B = 11
Now, substitute the value of B back into Equation 2:
M = 2(11) + 15
M = 22 + 15
M = 37
Therefore, Bailey is 11 years old and his mom is 37 years old.