the sum of the ages is 48, Bailey's mom is 15 more than twice his age. what is the ages of the two?

b is bailey and m is bailey's mom

b+m=48
given
m=2b+15;
substitute
2b+15+b=48
b=11;
where 11+m=48;
48-11=m;
m=37;
b=11 and m=37

Bailey --- x

Mom ---- 2x+15

solve
x + 2x+15 = 48

To solve this problem, let's break it down step by step.

1. Let's define the variables:
- Let Bailey's age be represented by the letter "B".
- Let Bailey's mom's age be represented by the letter "M".

2. According to the problem, the sum of their ages is 48:
B + M = 48

3. The problem also states that Bailey's mom is 15 more than twice his age:
M = 2B + 15

Now we have a system of two equations:
B + M = 48
M = 2B + 15

To solve this system, we can use the substitution method or the elimination method. Let's use the substitution method.

Solve Equation 2 for "M":
M = 2B + 15

Substitute this value into Equation 1:
B + (2B + 15) = 48

Combine like terms:
3B + 15 = 48

Subtract 15 from both sides:
3B = 33

Divide both sides by 3:
B = 11

Now, substitute the value of B back into Equation 2:
M = 2(11) + 15
M = 22 + 15
M = 37

Therefore, Bailey is 11 years old and his mom is 37 years old.