Posted by **amber** on Wednesday, May 4, 2011 at 10:48pm.

how to solve

y= (x-2)^2+4

4x+2y=14

algebraically

- geometry -
**MathMate**, Thursday, May 5, 2011 at 9:16am
By substitution:

y= (x-2)^2+4 ....(1)

4x+2y=14 ....(2)

Solve for y from (2) divided by 2:

2x+y=7

y=7-2x ...(2a)

Substitute (2a) in (1)

7-2x = (x-2)^2+4

Expand

7-2x = x^2-4x+4+4

x^2 -2x +1 = 0 ....(1a)

Solve 1(a) to get:

x=1 (duplicity 2)

Now substitute x=1 in (2a) to get

y=5

Substitute x=1,y=5 in (1) to check:

(1-2)^2+4 = 5 OK.

## Answer This Question

## Related Questions

- Geometry - How do solve the equations algebraically? x^2 + y^2 = 25 3y - 4x = 0
- pre-calculus 11 - I am asked to solve the absolute value equation of |1/2x +1...
- pre-calculus 11 - I am asked to solve the absolute value equation of |1/2x +1...
- Math - We have an important chemsitry test due and I want to make sure that I do...
- Algebra 2 - How do I do this f(x) = x - 5 (x + 4)^(1/2) when f(x) = -5 I know I ...
- Algebra - Solve each inequality algebraically:how do I solve this problem? What ...
- Math Gr 12 - We are learning to solve Factorable Polynomial Inequalities ...
- pre-cal - How do I find the domain of the following function algebraically? I ...
- Pre Calculas - 7. For the function defined by: f(x)= {x^2, x<=1} {2x+1, x>...
- solve algebraically - y=2x+6 x^2+y^2=8

More Related Questions