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posted by fakku on Wednesday, May 4, 2011 at 10:13pm.

The distance between (-3,-1) and (3,y) is sq rt45.Find y?

√((3+3)^2 + (y+1)^2 ) = √45 square both sides 36 + (y+1)^2 = 45 (y+1)^2 = 9 y+1 = ± 3 y = -1 ± 3 = 2 or -4

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