precalc
posted by anon .
find the domain and range of the following as an inequality and interval notation.
y=sqrtx3
2: y=3x+5
3: y= 2/x7
4; y=2+sqrt x

domain = set of all possible values of x
range = set of all possible values of y
therefore,
(1) y = sqrt(x3)
note that the term inside the sqrt can be zero but cannot be negative, for it will become imaginary. thus,
Domain: x must be greater than or equal to 3.
also, y can be zero (if x=3) but can never be negative since sqrt of any positive real number is always positive, thus,
Range: y must be greater than or equal to 0.
(2) y = 3x + 5
this is an equation of a line, and note that there is neither restriction in both x and y, thus,
Domain: x can be all real numbers
Range: y can be all real numbers
(3) y = 2/(x7)
note that denominators cannot be 0, thus,
Domain: x can be all real numbers except 7.
for the range, observe that y cannot be equal to zero, because, if so,
0 = 2/(x7) , then crossmultiplying,
0 = 2 , which is wrong, thus
Range: y is all real numbers except 0
(4) y = 2 + sqrt(x)
note that this is almost similar to #1, except that there is +2. therefore,
Domain: x must be greater than or equal to zero.
for the range, the minimum possible value of x is zero, but because there is +2,
Range: y must be greater than or equal to 2.
hope this helps~ :D