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If 1200 cal of heat are added to 50 g of water initially at a temperature of 15 oC, what is the final temperature of the water?

  • physics - ,

    the energy needed to increase or decrease the temperature of a given substance is given by
    Q = mc(T2-T1)
    Q = heat (in J or cal)
    m = mass (in g)
    c = specific heat capacity (in J/g*K or cal/g*K)
    T = temperature (in Kelvin)
    **change in temperature can have unit degree Celsius or Kelvin,, thus you can use it interchangeably (what i mean is that the units for c can also be J/(g*C))
    Q: (+) when heat is absorbed by substance
    Q: (-) when heat is released from substance
    for water, c = 1 cal/g*K.
    1200 = (50)(1)(T2 - 15)
    1200 = 50*(T2) - 750
    1950 = 50*(T2)
    T2 = 39 deg C

    hope this helps~ :)

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