Posted by **Please Help** on Wednesday, May 4, 2011 at 9:26pm.

The square root of 27b^11

Can someone explain to me how to solve this?

- Math -
**Jai**, Wednesday, May 4, 2011 at 9:41pm
first, we factor the radicand (the term inside the radical sign or the squreroot):

sqrt(27*b^11)

sqrt[ (3*3*3) (b*b^10) ]

then we separate the perfect squares:

sqrt[ 3*(3^2) b*((b^5)^2) ]

and we take the squarerrot of the perfect squres. the squareroot of 3^2 is 3, while (b^5)^2 is b^5, then we can take them out of the sqrt, leaving only the 3 and b inside:

3b^5 * sqrt(3b)

hope this helps~ :)

## Answer this Question

## Related Questions

- Advanced Algebra - Can you please explain to me how I can solve these problems...
- Math - The square root of 27b 11 squared ( square root 27^11)
- Math - Could someone please help me with this math problem? This is what I have ...
- Algebra - Use the quadratic formula to solve the equation. Give exact answers: ...
- Math simplifying mixed radicals - Please help me simplify these following mixed ...
- Calculus/Logarithms - Find the derivative of f(x) = (square root of x)(ln x). ...
- math - 2.)If f(x)=3x,g(x)=x-3,and h(x)= the square root of x, find (fogox)(X). ...
- math - 2.)If f(x)=3x,g(x)=x-3,and h(x)= the square root of x, find (fogox)(X). ...
- Math ~CHECK MY ANSWER~ - 1) Which of these is a rational number? a. Pi b. Square...
- math - determine the area of triangle abc when side ab= square root of x, side ...

More Related Questions