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September 30, 2014

September 30, 2014

Posted by **kate** on Wednesday, May 4, 2011 at 8:26pm.

- calculus - integration? -
**MathMate**, Wednesday, May 4, 2011 at 10:53pmf(x) = e^(sin(x))cos(x)

I=∫f(x)

= ∫e^(sin(x))cos(x)dx

use substitution u=sin(x),

du=cos(x)dx

I=∫e^u du

=e^u +C'

=e^(sin(x))+C

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