Sunday

December 21, 2014

December 21, 2014

Posted by **kathy** on Wednesday, May 4, 2011 at 7:34pm.

- math -
**Mgraph**, Wednesday, May 4, 2011 at 9:11pmThe equation x^3-4x^2+16=0 has 1 real root

x=-1.68 (approx)

(x^4-4x^3+16x)'=4x^3-12x^2+16=4(x^3-3x^2+4)=4(x+1)(x^2-4x+4)=4(x+1)(x-2)^2

(x^4-4x^3+16x)''=12x^2-24x=12x(x-2)

**Answer this Question**

**Related Questions**

Math-due today, need a check - Please help me with this, below is a question I ...

Math - How would you write open intervals for concavity? After you find the ...

Math/Algebra - Please help me with this, below is a question I have to answer…...

calculus - hi i am having trouble solving this example of finding the derivate ...

Trigonometry - Graph the function y=2sin(x-2pi/3). To draw the graph, plot all x...

Calculus - Sketch the graph of f(x)=x^2/x-2. Identify the domain, x-intercepts, ...

Math - 2x(x+3) = 0 Is there a way to solve that using the below methods? ...

calculus - im having so much trouble figuring out how to get these answers. i ...

PreCalculus - I'm trying to find the x-intercepts of a polynomial function = 4x^...

math - Using the equation y=(3x+2)(x+2) determine the x intercepts, the axis of ...