Post a New Question

algebra

posted by on .

The sum of the squares of two consecutive odd integers decreased by the product of the integers is the same as sixty-seven.

  • algebra - ,

    (n)^2 + (n+2)^2 - n(n+2)=67
    solve for n, then n+2

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question