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September 30, 2014

September 30, 2014

Posted by **Tom** on Wednesday, May 4, 2011 at 6:17pm.

Females:

62,69,70,72,78,77,79,83,80,88,90,90,98,100, 66,67,65,63,69, 83

Can you hellp me I need to find:

A) P value and the Z value of this data with a Alpha Value of 0.05.

- MATH Please help me -
**PsyDAG**, Thursday, May 5, 2011 at 11:17amFind the mean first = sum of scores/number of scores

Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.

Standard deviation = square root of variance

For two-tailed test, P = .05 for Z = 1.645.

I'll let you do the calculations.

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