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The height above the ground of a ball thrown up with a velocity of 96 feet per second from a height of 6 feet is 6+96t-16^2 feet, where t is the time in seconds. According to this model, how high is the ball after 7 seconds? Explain (Thank you in advance! :)

  • algebra -

    6 = 6 + 96t - 16t^2
    16t^2 - 96t = 0
    16t(t - 6t)=0
    t = 0 or t = 6

    the ball was 6 feet high at the beginning (t=0) and
    on it way back down at 6 seconds later.
    (I bet the ball was at its highest point after 3 seconds)

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