Posted by **Matthew** on Wednesday, May 4, 2011 at 6:14pm.

The height above the ground of a ball thrown up with a velocity of 96 feet per second from a height of 6 feet is 6+96t-16^2 feet, where t is the time in seconds. According to this model, how high is the ball after 7 seconds? Explain (Thank you in advance! :)

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