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April 23, 2014

April 23, 2014

Posted by **Mike** on Wednesday, May 4, 2011 at 5:00pm.

Use the function, y=-(x+1)^2 +2, to answer the following parts.

Find the y-intercept

y=-(0+1)^2 +2

y=-(1)^2 +2

y=-1+2

y=1 is my answer

Find the x-intercept

0=-(x+1)^2 +2

0=-((x^2)+(1^2))+2

0=-x^2 - 1 + 2

sq.rt(x^2)= sq.rt(1)

x=1 is my answer but im not sure about it.

Finding the vertex, increasing interval,and decreasing interval.

Is the vertex (-1,2)

Increasing interval (-2,1)

Decreasing interval(1,-2)

Do the x-intercept =1?

- algebra -
**Reiny**, Wednesday, May 4, 2011 at 5:48pmYour y-intercept is correct

for the x-intercept, you started correctly

0 = -(x+1)^2 + 2

(x+1)^1 = 2

take √ of both sides

x+1 = ± √2

x = -1 + √2 or x = -1 - √2

vertex is correct

increasing : x < -1

decreasing : x > 1

( change it to whatever notation you use to state the interval.)

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