Posted by Mike on .
Im having a hard time figuring out this problem:
Use the function, y=(x+1)^2 +2, to answer the following parts.
Find the yintercept
y=(0+1)^2 +2
y=(1)^2 +2
y=1+2
y=1 is my answer
Find the xintercept
0=(x+1)^2 +2
0=((x^2)+(1^2))+2
0=x^2  1 + 2
sq.rt(x^2)= sq.rt(1)
x=1 is my answer but im not sure about it.
Finding the vertex, increasing interval,and decreasing interval.
Is the vertex (1,2)
Increasing interval (2,1)
Decreasing interval(1,2)
Do the xintercept =1?

algebra 
Reiny,
Your yintercept is correct
for the xintercept, you started correctly
0 = (x+1)^2 + 2
(x+1)^1 = 2
take √ of both sides
x+1 = ± √2
x = 1 + √2 or x = 1  √2
vertex is correct
increasing : x < 1
decreasing : x > 1
( change it to whatever notation you use to state the interval.)