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April 16, 2014

April 16, 2014

Posted by **jesus gonzalez** on Wednesday, May 4, 2011 at 12:11pm.

- math -
**MathMate**, Wednesday, May 4, 2011 at 4:40pmWe note that the series is a geometric series with a common ratio of r=16/4=4

The first term, i=1, is given by

4=1*4^1=4^i

The second term, i=2, is given by

16=4^2=4^i

...

and the last term, i=5, is given by

1024=4^5=4^i

Therefore the summation is for

4^i for i=1 to i=5.

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