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Mathematics
Algebra
Arithmetic Series
The first term in an arithmetic series is 7 and the 17th is 49. What is the 20th term?
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The 9th term of an arithmetic sequence is 12 and the 17th term is 28, find the 4th term of the arithmetic sequences
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9th term = a+8d = 12 17th term= a+16d = 28 subtract them 8d = 16 d = 2 sub into a+8d = 12 a = -4 4th
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In an arithmetic series, the terms of the series are equally spread out. For example, in
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have you learned this property ? S(n) = (n/2)(first + last) ? 1390 = (n/2)(3 + 136) I get n = 20 so
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An arithmetic series has first term 5 and a common difference 7
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Tn = 5 + 7(n-1) = 7n-2 S38 = 38/2 (2*5 + 37*7)
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The sum of the 1st nine terms of an arithmetic series is 216. The 1st,3rd and the 7th terms of series form the 1st three terms
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just write what they told you: 9/2 (2a+8d) = 216 (a+2d)/(a) = (a+6d)/(a+2d) Now solve for a and d.
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In an arithmetic series the 3rd term is -8 and 12th term is -35. Determine the number of terms in the series if its sum is -100
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a+2d = -8 a+11d = -35 so, 9d = -27 Now you can find a and d, and then solve n/2 (2a+(n-1)d) = -100 n
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An arithmetic series has nine terms ,4th term is10 and the 7th term is 16 .Find the sum of the series
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d = (16-10)/(7-4) = 2 a = 10-3d = 4 S9 = 9/2 (2*4+8*2) = 108
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The sum of an arithmetic series is1,9,5 of the first term is 5 and the difference is 8,find the number of term in series
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To solve this problem, we can use the formula for the sum of an arithmetic series: Sn = (n/2)(2a +
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An arithmetic series has first term -50 and common difference 4. How many terms are in the series so that the sum of the series
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Again, use your definition. you know S(n) = (n/2)(2a + (n-1)d ), so (n/2)(2a + (n-1)d ) > 100 and
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