Posted by **Mike** on Wednesday, May 4, 2011 at 9:43am.

Im having a hard time figuring out this problem:

Use the function, y=-(x+1)^2 +2, to answer the following parts.

Find the y-intercept

y=-(0+1)^2 +2

y=-(1)^2 +2

y=-1+2

y=1 is my answer

Find the x-intercept

0=-(x+1)^2 +2

0=-((x^2)+(1^2))+2

0=-x^2 - 1 + 2

sq.rt(x^2)= sq.rt(1)

x=1 is my answer but im not sure about it.

I need help with:

Finding the vertex, increasing interval,and decreasing interval.

- Algebra -
**Mike**, Wednesday, May 4, 2011 at 12:04pm
Is the vertex (-1,2)

Increasing interval (-2,1)

Decreasing interval(1,-2)

Do the x-intercept =1?

- Algebra -
**Henry**, Thursday, May 5, 2011 at 8:13pm
1. y= 1 is correct.

2. Y = -(X+1)^2 + 2 = 0,

-(X+1)^2 = -2,

Divide both sides by -1:

(X+1)^2 = 2,

Take sqrt of both sides:

X+1 = sqrt2 = 1.4142,

X = 1.4142 - 1 = 0.4142. = x-Intercept

3. V(-1,2) is correct.

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