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March 27, 2017

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Im having a hard time figuring out this problem:

Use the function, y=-(x+1)^2 +2, to answer the following parts.

Find the y-intercept
y=-(0+1)^2 +2
y=-(1)^2 +2
y=-1+2
y=1 is my answer

Find the x-intercept
0=-(x+1)^2 +2
0=-((x^2)+(1^2))+2
0=-x^2 - 1 + 2
sq.rt(x^2)= sq.rt(1)
x=1 is my answer but im not sure about it.

I need help with:
Finding the vertex, increasing interval,and decreasing interval.

  • Algebra - ,

    Is the vertex (-1,2)
    Increasing interval (-2,1)
    Decreasing interval(1,-2)

    Do the x-intercept =1?

  • Algebra - ,

    1. y= 1 is correct.

    2. Y = -(X+1)^2 + 2 = 0,
    -(X+1)^2 = -2,
    Divide both sides by -1:
    (X+1)^2 = 2,
    Take sqrt of both sides:
    X+1 = sqrt2 = 1.4142,
    X = 1.4142 - 1 = 0.4142. = x-Intercept

    3. V(-1,2) is correct.

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